Two-Atom Resonant Transfer

Two hydrogen atoms — identical, so resonant. Atom A drops n=2→n=1 and emits a Lyman-α photon; atom B, in the ground state, absorbs that exact photon and climbs n=1→n=2. The excitation crosses from A to B carried by one 10.2 eV photon, and then back. A's emission is B's absorption — the same photon, the same energy, because they are the same atom twice. That is the two-transcriber hand-off with nothing added: the photon is the crossing.

Bridge-Burners LLC · Fiddler · A·emit = B·absorb · resonant Lyman-α transfer · anchor: AKASHA

State

excitation onA
photonheld by A
transfers (hops)0
escaped (missed)0

Bare numbers

photon10.2 eV · 121.6 nm · Lyman-α (UV)
resonanceA·emit energy = B·absorb energy (both H)
conservedthe 10.2 eV excitation, carried by the photon
nameradiation trapping / resonant scattering

Status discipline

LiteralIdentical atoms are resonant; A's Lyman-α emission is exactly B's absorption energy; excitation transfers A→B by one photon. This is how Lyman-α random-walks out of H gas.
BridgeThe two atoms as the two transcribers; the shared photon as the crossing / hand-off; the ping-pong as the figure-eight.
SpeculativeThe clean A↔B line is idealized — real emission is isotropic, so transfer is a random walk (toggle "Isotropic"). Bohr orbits are a cartoon of the 1s/2p cloud.