Bare chemistry: a hydrogen atom is a two-photon transcriber. A photon goes in, the electron climbs n=1→n=2 and holds, then drops and a photon goes out — and the atom is unchanged at both ends. That is the even palindrome made literal: e (electron) · p (photon in) · g·g (the held excited turn) · p (photon out) · e. The ×2 photons are the two p's. Real numbers: ΔE = 10.2 eV, λ = 121.6 nm — Lyman-α, in the UV.
Bridge-Burners LLC · Fiddler · h | transcriber (×2 photon) | h · e(p(g·g)p)e · anchor: AKASHA
e ( p ( g · g ) p ) e
State
phaseground
leveln = 1
photons in / out0 / 0
palindrome ate
Bare numbers (H)
E₁ , E₂
−13.6 eV , −3.4 eV (Eₙ = −13.6/n²)
ΔE
10.2 eV — the photon energy
λ
121.6 nm — Lyman-α, ultraviolet
r₁ , r₂
0.53 Å , 2.12 Å (rₙ = n²·a₀)
Status discipline
LiteralH levels Eₙ=−13.6/n²; n=1↔2 is 10.2 eV / 121.6 nm; absorption lifts, emission drops, photon energy = ΔE.
BridgeThe atom as a transcriber: photon in → held excited turn → photon out, e(p(g·g)p)e.
SpeculativeThe circular Bohr orbit is a picture — real H is a 1s/2p probability cloud; Bohr gets the energy right, the shape wrong.