full torus · 9 quads

0 / 81

named 720s

e⁻ seated

sing

your count

forward front 720 · forward middle 720 · forward back 720

middle front 720 · middle middle 720 · middle back 720

back front 720 · back middle 720 · back back 720

That is the whole 3×3 sheet. Nine chairs. One traveler was one electron. Pauli on this sheet seats one fermion per quad — so the torus is empty until nine are sitting.

the sing

spinor period = 4π = 720° (SU(2) double cover of SO(3))

one lap = 2π → sign(ψ) = −1 · not home

tick = 720° / 9 = 80° = 4π/9

sheet × ticks = 9 × 9 = 81

(3×3)² = 3⁴ = 81 (3×3)³ = 9³ = 729

space-cube 3×3×3 = 27 quads, still not 81

occupancy

Pauli lockn ≤ 1 per quad

sheet fill9 e⁻ · 9 quads

second e⁻ in one quadforbidden

sign at 360°−1, same electron

home+1 only at 720°

live

tick0 / 81

active quadforward front

local turn0°

sign+1

seated0 / 9

stamps

LITyour nine names exhaust the sheet

LIT720° / 9 = 80° · 9×9 = 81

AMBER((3×3))³ is 729. 81 is the square.

HOT1 e⁻ / quad is the instrument Pauli, not QED

what is not being claimed

This is a finite occupancy picture on a torus of revolution. It is not a derivation of the exclusion principle, not a count of states in a real atom, and not a claim that spacetime is a 3×3×3 lattice. The beauty is the sheet. The math that survives the beauty is the double cover and the 81 = 9×9 tick count.