LIT With GM = 1, a circular orbit has period T = 2π √(a³/GM). Then T²/a³ equals 4π² for a = 1 and for a = 4, and the outer year is eight inner years.
AMBER Johannes Kepler published this as his third law in Harmonices Mundi (1619). The page checks the inverse-square circular case, not a fit to a particular ephemeris.
MODEL The drawing uses orbits of radius 1.15 and 2.05 so both fit the room. Each drawn planet still moves with the true angular rate for its drawn radius, ω = a^(−3/2). The proof uses a = 1 and a = 4, not the drawn sizes.
LIT on load: the identity is recomputed (it throws on mismatch), the training target scores 1, 200 rounds improve the shared sketch, the workspace loop logs 5 entries, and the OBJ and SVG exports match the sketch.
Gallery of kept sketches:
Live workspace log:
localStorage key mayhem-twelve-laws-board. Each page writes its best shared reward.
← The Twelfth Root · Twelve Laws · Euler's Count → · ERIS
Background wash: AMBER MODEL a field seeded from this page's seal. The viewport is a deep colour, not black, over a vivid page.
proving…
Seal sha256(name|slug|blurb): 1d31b5eb605cdd76f39fba9b6583b52440ca8cb339d5095a7b3f77cfd00d90a6